Comments on: For 1.8 mole of the radioactive isotope molybdenum-99, half-life = 67 hours, how many disintegrations have occ

Comments on: For 1.8 mole of the radioactive isotope molybdenum-99, half-life = 67 hours, how many disintegrations have occ http://molybdenuminfo.com/2008/11/08/for-18-mole-of-the-radioactive-isotope-molybdenum-99-half-life-67-hours-how-many-disintegrations-have-occ/ Answering your molybdenum questions Tue, 07 Feb 2012 13:39:24 +0000 http://wordpress.org/?v=2.6.3 By: Liv http://molybdenuminfo.com/2008/11/08/for-18-mole-of-the-radioactive-isotope-molybdenum-99-half-life-67-hours-how-many-disintegrations-have-occ/#comment-78 Liv Tue, 11 Nov 2008 09:35:33 +0000 http://molybdenuminfo.com/?p=96#comment-78 67 hours = 4020 minutes 17 minutes = 0.283 hours ln 2 / 67 hrs = 0.0103/hr N(.283) = 1.8 x e^ (-.0103 x .283) = 1.8 x .9971 = 1.7947 moles remaining 1.8 mol - 1.7947 mol = 0.00522 moles .00522 x (6.02e23) = 3.14e21 67 hours = 4020 minutes
17 minutes = 0.283 hours

ln 2 / 67 hrs = 0.0103/hr

N(.283) = 1.8 x e^ (-.0103 x .283)
= 1.8 x .9971
= 1.7947 moles remaining

1.8 mol - 1.7947 mol = 0.00522 moles

.00522 x (6.02e23) = 3.14e21

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